Solve for x
x=1500\sqrt{3}-2500\approx 98.076211353
x=-1500\sqrt{3}-2500\approx -5098.076211353
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x^{2}+5000x-500000=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-5000±\sqrt{5000^{2}-4\left(-500000\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 5000 for b, and -500000 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-5000±\sqrt{25000000-4\left(-500000\right)}}{2}
Square 5000.
x=\frac{-5000±\sqrt{25000000+2000000}}{2}
Multiply -4 times -500000.
x=\frac{-5000±\sqrt{27000000}}{2}
Add 25000000 to 2000000.
x=\frac{-5000±3000\sqrt{3}}{2}
Take the square root of 27000000.
x=\frac{3000\sqrt{3}-5000}{2}
Now solve the equation x=\frac{-5000±3000\sqrt{3}}{2} when ± is plus. Add -5000 to 3000\sqrt{3}.
x=1500\sqrt{3}-2500
Divide -5000+3000\sqrt{3} by 2.
x=\frac{-3000\sqrt{3}-5000}{2}
Now solve the equation x=\frac{-5000±3000\sqrt{3}}{2} when ± is minus. Subtract 3000\sqrt{3} from -5000.
x=-1500\sqrt{3}-2500
Divide -5000-3000\sqrt{3} by 2.
x=1500\sqrt{3}-2500 x=-1500\sqrt{3}-2500
The equation is now solved.
x^{2}+5000x-500000=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
x^{2}+5000x-500000-\left(-500000\right)=-\left(-500000\right)
Add 500000 to both sides of the equation.
x^{2}+5000x=-\left(-500000\right)
Subtracting -500000 from itself leaves 0.
x^{2}+5000x=500000
Subtract -500000 from 0.
x^{2}+5000x+2500^{2}=500000+2500^{2}
Divide 5000, the coefficient of the x term, by 2 to get 2500. Then add the square of 2500 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+5000x+6250000=500000+6250000
Square 2500.
x^{2}+5000x+6250000=6750000
Add 500000 to 6250000.
\left(x+2500\right)^{2}=6750000
Factor x^{2}+5000x+6250000. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+2500\right)^{2}}=\sqrt{6750000}
Take the square root of both sides of the equation.
x+2500=1500\sqrt{3} x+2500=-1500\sqrt{3}
Simplify.
x=1500\sqrt{3}-2500 x=-1500\sqrt{3}-2500
Subtract 2500 from both sides of the equation.
x ^ 2 +5000x -500000 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = -5000 rs = -500000
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = -2500 - u s = -2500 + u
Two numbers r and s sum up to -5000 exactly when the average of the two numbers is \frac{1}{2}*-5000 = -2500. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(-2500 - u) (-2500 + u) = -500000
To solve for unknown quantity u, substitute these in the product equation rs = -500000
6250000 - u^2 = -500000
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = -500000-6250000 = -6750000
Simplify the expression by subtracting 6250000 on both sides
u^2 = 6750000 u = \pm\sqrt{6750000} = \pm \sqrt{6750000}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =-2500 - \sqrt{6750000} = -5098.076 s = -2500 + \sqrt{6750000} = 98.076
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.
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