Solve x^2+4y-12=0

$$x ^ { 2 } + 4 y - 12 = 0$$

Solve for y

$$y=-\frac{x^{2}}{4}+3$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides. Anything subtracted from zero gives its negation.

$$4y-12=-x^{2}$$

Add 12 to both sides.

$$4y=-x^{2}+12$$

The equation is in standard form.

$$4y=12-x^{2}$$

Divide both sides by 4.

$$\frac{4y}{4}=\frac{12-x^{2}}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$y=\frac{12-x^{2}}{4}$$

Divide -x^{2}+12 by 4.

$$y=-\frac{x^{2}}{4}+3$$

Solve for x (complex solution)

$$x=-2\sqrt{3-y}$$

$$x=2\sqrt{3-y}$$

Solve for x

$$x=2\sqrt{3-y}$$

$$x=-2\sqrt{3-y}\text{, }y\leq 3$$