Solve x^2+4bx+324=0

$$x ^ { 2 } + 4 b x + 324 = 0$$

Solve for b

$$b=-\frac{x}{4}-\frac{81}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides. Anything subtracted from zero gives its negation.

$$4bx+324=-x^{2}$$

Subtract 324 from both sides.

$$4bx=-x^{2}-324$$

The equation is in standard form.

$$4xb=-x^{2}-324$$

Divide both sides by 4x.

$$\frac{4xb}{4x}=\frac{-x^{2}-324}{4x}$$

Dividing by 4x undoes the multiplication by 4x.

$$b=\frac{-x^{2}-324}{4x}$$

Divide -x^{2}-324 by 4x.

$$b=-\frac{x}{4}-\frac{81}{x}$$

Solve for x (complex solution)

$$x=2\sqrt{b^{2}-81}-2b$$

$$x=-2\sqrt{b^{2}-81}-2b$$

Solve for x

$$x=2\sqrt{b^{2}-81}-2b$$

$$x=-2\sqrt{b^{2}-81}-2b\text{, }|b|\geq 9$$