Solve x^2+36=2

$$x ^ { 2 } + 36 = 2$$

Solve for x (complex solution)

$$x=-\sqrt{34}i\approx -0-5.830951895i$$

$$x=\sqrt{34}i\approx 5.830951895i$$

Steps by Finding Square Root

Subtract 36 from both sides.

$$x^{2}=2-36$$

Subtract 36 from 2 to get -34.

$$x^{2}=-34$$

The equation is now solved.

$$x=\sqrt{34}i x=-\sqrt{34}i$$

Steps Using the Quadratic Formula

Subtract 2 from both sides.

$$x^{2}+36-2=0$$

Subtract 2 from 36 to get 34.

$$x^{2}+34=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and 34 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 34}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\times 34}}{2}$$

Multiply -4 times 34.

$$x=\frac{0±\sqrt{-136}}{2}$$

Take the square root of -136.

$$x=\frac{0±2\sqrt{34}i}{2}$$

Now solve the equation x=\frac{0±2\sqrt{34}i}{2} when ± is plus.

$$x=\sqrt{34}i$$

Now solve the equation x=\frac{0±2\sqrt{34}i}{2} when ± is minus.

$$x=-\sqrt{34}i$$

The equation is now solved.

$$x=\sqrt{34}i x=-\sqrt{34}i$$