Solve for y
y=\frac{z-x^{2}}{3}
Solve for x
x=\sqrt{z-3y}
x=-\sqrt{z-3y}\text{, }y\leq \frac{z}{3}
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3y=z-x^{2}
Subtract x^{2} from both sides.
\frac{3y}{3}=\frac{z-x^{2}}{3}
Divide both sides by 3.
y=\frac{z-x^{2}}{3}
Dividing by 3 undoes the multiplication by 3.
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