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Solve for x (complex solution)
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x^{2}+3x+5-x=-2
Subtract x from both sides.
x^{2}+2x+5=-2
Combine 3x and -x to get 2x.
x^{2}+2x+5+2=0
Add 2 to both sides.
x^{2}+2x+7=0
Add 5 and 2 to get 7.
x=\frac{-2±\sqrt{2^{2}-4\times 7}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 2 for b, and 7 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-2±\sqrt{4-4\times 7}}{2}
Square 2.
x=\frac{-2±\sqrt{4-28}}{2}
Multiply -4 times 7.
x=\frac{-2±\sqrt{-24}}{2}
Add 4 to -28.
x=\frac{-2±2\sqrt{6}i}{2}
Take the square root of -24.
x=\frac{-2+2\sqrt{6}i}{2}
Now solve the equation x=\frac{-2±2\sqrt{6}i}{2} when ± is plus. Add -2 to 2i\sqrt{6}.
x=-1+\sqrt{6}i
Divide -2+2i\sqrt{6} by 2.
x=\frac{-2\sqrt{6}i-2}{2}
Now solve the equation x=\frac{-2±2\sqrt{6}i}{2} when ± is minus. Subtract 2i\sqrt{6} from -2.
x=-\sqrt{6}i-1
Divide -2-2i\sqrt{6} by 2.
x=-1+\sqrt{6}i x=-\sqrt{6}i-1
The equation is now solved.
x^{2}+3x+5-x=-2
Subtract x from both sides.
x^{2}+2x+5=-2
Combine 3x and -x to get 2x.
x^{2}+2x=-2-5
Subtract 5 from both sides.
x^{2}+2x=-7
Subtract 5 from -2 to get -7.
x^{2}+2x+1^{2}=-7+1^{2}
Divide 2, the coefficient of the x term, by 2 to get 1. Then add the square of 1 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+2x+1=-7+1
Square 1.
x^{2}+2x+1=-6
Add -7 to 1.
\left(x+1\right)^{2}=-6
Factor x^{2}+2x+1. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+1\right)^{2}}=\sqrt{-6}
Take the square root of both sides of the equation.
x+1=\sqrt{6}i x+1=-\sqrt{6}i
Simplify.
x=-1+\sqrt{6}i x=-\sqrt{6}i-1
Subtract 1 from both sides of the equation.