Solve x^2+2.4*10^-4x-4.08*10^-5

$$x ^ { 2 } + 2.4 \times 10 ^ { - 4 } x - 4.08 \times 10 ^ { - 5 }$$

Evaluate

$$x^{2}+\frac{3x}{12500}-0.0000408$$

Solution Steps

Calculate 10 to the power of -4 and get \frac{1}{10000}.

$$x^{2}+2.4\times \frac{1}{10000}x-4.08\times 10^{-5}$$

Multiply 2.4 and \frac{1}{10000} to get \frac{3}{12500}.

$$x^{2}+\frac{3}{12500}x-4.08\times 10^{-5}$$

Calculate 10 to the power of -5 and get \frac{1}{100000}.

$$x^{2}+\frac{3}{12500}x-4.08\times \frac{1}{100000}$$

Multiply 4.08 and \frac{1}{100000} to get \frac{51}{1250000}.

$$x^{2}+\frac{3}{12500}x-\frac{51}{1250000}$$

Factor

$$\left(x-\frac{-\sqrt{25509}-3}{25000}\right)\left(x-\frac{\sqrt{25509}-3}{25000}\right)$$