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x^{2}+5.76=3^{2}
Calculate 2.4 to the power of 2 and get 5.76.
x^{2}+5.76=9
Calculate 3 to the power of 2 and get 9.
x^{2}+5.76-9=0
Subtract 9 from both sides.
x^{2}-3.24=0
Subtract 9 from 5.76 to get -3.24.
\left(x-\frac{9}{5}\right)\left(x+\frac{9}{5}\right)=0
Consider x^{2}-3.24. Rewrite x^{2}-3.24 as x^{2}-\left(\frac{9}{5}\right)^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
x=\frac{9}{5} x=-\frac{9}{5}
To find equation solutions, solve x-\frac{9}{5}=0 and x+\frac{9}{5}=0.
x^{2}+5.76=3^{2}
Calculate 2.4 to the power of 2 and get 5.76.
x^{2}+5.76=9
Calculate 3 to the power of 2 and get 9.
x^{2}=9-5.76
Subtract 5.76 from both sides.
x^{2}=3.24
Subtract 5.76 from 9 to get 3.24.
x=\frac{9}{5} x=-\frac{9}{5}
Take the square root of both sides of the equation.
x^{2}+5.76=3^{2}
Calculate 2.4 to the power of 2 and get 5.76.
x^{2}+5.76=9
Calculate 3 to the power of 2 and get 9.
x^{2}+5.76-9=0
Subtract 9 from both sides.
x^{2}-3.24=0
Subtract 9 from 5.76 to get -3.24.
x=\frac{0±\sqrt{0^{2}-4\left(-3.24\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -3.24 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-3.24\right)}}{2}
Square 0.
x=\frac{0±\sqrt{12.96}}{2}
Multiply -4 times -3.24.
x=\frac{0±\frac{18}{5}}{2}
Take the square root of 12.96.
x=\frac{9}{5}
Now solve the equation x=\frac{0±\frac{18}{5}}{2} when ± is plus.
x=-\frac{9}{5}
Now solve the equation x=\frac{0±\frac{18}{5}}{2} when ± is minus.
x=\frac{9}{5} x=-\frac{9}{5}
The equation is now solved.