Solve x^2+2^2=(4-x)^2

$$x ^ { 2 } + 2 ^ { 2 } = ( 4 - x ) ^ { 2 }$$

Solve for x

$$x = \frac{3}{2} = 1\frac{1}{2} = 1.5$$

Steps for Solving Linear Equation

Calculate 2 to the power of 2 and get 4.

$$x^{2}+4=\left(4-x\right)^{2}$$

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(4-x\right)^{2}.

$$x^{2}+4=16-8x+x^{2}$$

Add 8x to both sides.

$$x^{2}+4+8x=16+x^{2}$$

Subtract x^{2} from both sides.

$$x^{2}+4+8x-x^{2}=16$$

Combine x^{2} and -x^{2} to get 0.

$$4+8x=16$$

Subtract 4 from both sides.

$$8x=16-4$$

Subtract 4 from 16 to get 12.

$$8x=12$$

Divide both sides by 8.

$$x=\frac{12}{8}$$

Reduce the fraction \frac{12}{8} to lowest terms by extracting and canceling out 4.

$$x=\frac{3}{2}$$