Solve x^2+144=(x+5)^2

$$x ^ { 2 } + 144 = ( x + 5 ) ^ { 2 }$$

Solve for x

$$x = \frac{119}{10} = 11\frac{9}{10} = 11.9$$

Steps for Solving Linear Equation

Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+5\right)^{2}.

$$x^{2}+144=x^{2}+10x+25$$

Subtract x^{2} from both sides.

$$x^{2}+144-x^{2}=10x+25$$

Combine x^{2} and -x^{2} to get 0.

$$144=10x+25$$

Swap sides so that all variable terms are on the left hand side.

$$10x+25=144$$

Subtract 25 from both sides.

$$10x=144-25$$

Subtract 25 from 144 to get 119.

$$10x=119$$

Divide both sides by 10.

$$x=\frac{119}{10}$$