Solve for x
x=\frac{\sqrt{109}-13}{2}\approx -1.279846746
x=\frac{-\sqrt{109}-13}{2}\approx -11.720153254
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x^{2}+13x+15=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-13±\sqrt{13^{2}-4\times 15}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 13 for b, and 15 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-13±\sqrt{169-4\times 15}}{2}
Square 13.
x=\frac{-13±\sqrt{169-60}}{2}
Multiply -4 times 15.
x=\frac{-13±\sqrt{109}}{2}
Add 169 to -60.
x=\frac{\sqrt{109}-13}{2}
Now solve the equation x=\frac{-13±\sqrt{109}}{2} when ± is plus. Add -13 to \sqrt{109}.
x=\frac{-\sqrt{109}-13}{2}
Now solve the equation x=\frac{-13±\sqrt{109}}{2} when ± is minus. Subtract \sqrt{109} from -13.
x=\frac{\sqrt{109}-13}{2} x=\frac{-\sqrt{109}-13}{2}
The equation is now solved.
x^{2}+13x+15=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
x^{2}+13x+15-15=-15
Subtract 15 from both sides of the equation.
x^{2}+13x=-15
Subtracting 15 from itself leaves 0.
x^{2}+13x+\left(\frac{13}{2}\right)^{2}=-15+\left(\frac{13}{2}\right)^{2}
Divide 13, the coefficient of the x term, by 2 to get \frac{13}{2}. Then add the square of \frac{13}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+13x+\frac{169}{4}=-15+\frac{169}{4}
Square \frac{13}{2} by squaring both the numerator and the denominator of the fraction.
x^{2}+13x+\frac{169}{4}=\frac{109}{4}
Add -15 to \frac{169}{4}.
\left(x+\frac{13}{2}\right)^{2}=\frac{109}{4}
Factor x^{2}+13x+\frac{169}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+\frac{13}{2}\right)^{2}}=\sqrt{\frac{109}{4}}
Take the square root of both sides of the equation.
x+\frac{13}{2}=\frac{\sqrt{109}}{2} x+\frac{13}{2}=-\frac{\sqrt{109}}{2}
Simplify.
x=\frac{\sqrt{109}-13}{2} x=\frac{-\sqrt{109}-13}{2}
Subtract \frac{13}{2} from both sides of the equation.
x ^ 2 +13x +15 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = -13 rs = 15
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = -\frac{13}{2} - u s = -\frac{13}{2} + u
Two numbers r and s sum up to -13 exactly when the average of the two numbers is \frac{1}{2}*-13 = -\frac{13}{2}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(-\frac{13}{2} - u) (-\frac{13}{2} + u) = 15
To solve for unknown quantity u, substitute these in the product equation rs = 15
\frac{169}{4} - u^2 = 15
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = 15-\frac{169}{4} = -\frac{109}{4}
Simplify the expression by subtracting \frac{169}{4} on both sides
u^2 = \frac{109}{4} u = \pm\sqrt{\frac{109}{4}} = \pm \frac{\sqrt{109}}{2}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =-\frac{13}{2} - \frac{\sqrt{109}}{2} = -11.720 s = -\frac{13}{2} + \frac{\sqrt{109}}{2} = -1.280
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.
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