Solve x^2+12x-9y=0

$$x ^ { 2 } + 12 x - 9 y = 0$$

Solve for y

$$y=\frac{x\left(x+12\right)}{9}$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides. Anything subtracted from zero gives its negation.

$$12x-9y=-x^{2}$$

Subtract 12x from both sides.

$$-9y=-x^{2}-12x$$

Divide both sides by -9.

$$\frac{-9y}{-9}=-\frac{x\left(x+12\right)}{-9}$$

Dividing by -9 undoes the multiplication by -9.

$$y=-\frac{x\left(x+12\right)}{-9}$$

Divide -x\left(12+x\right) by -9.

$$y=\frac{x\left(x+12\right)}{9}$$

Solve for x (complex solution)

$$x=3\sqrt{y+4}-6$$

$$x=-3\sqrt{y+4}-6$$

Solve for x

$$x=3\sqrt{y+4}-6$$

$$x=-3\sqrt{y+4}-6\text{, }y\geq -4$$