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x^{2}+144=\left(x+6\right)^{2}
Calculate 12 to the power of 2 and get 144.
x^{2}+144=x^{2}+12x+36
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+6\right)^{2}.
x^{2}+144-x^{2}=12x+36
Subtract x^{2} from both sides.
144=12x+36
Combine x^{2} and -x^{2} to get 0.
12x+36=144
Swap sides so that all variable terms are on the left hand side.
12x=144-36
Subtract 36 from both sides.
12x=108
Subtract 36 from 144 to get 108.
x=\frac{108}{12}
Divide both sides by 12.
x=9
Divide 108 by 12 to get 9.