Solve x^2+1x+28=(7+x)*w

$$x ^ { 2 } + 1 x + 28 = ( 7 + x ) \times w$$

Solve for w

$$w=\frac{x^{2}+x+28}{x+7}$$

$$x\neq -7$$

Steps for Solving Linear Equation

Use the distributive property to multiply 7+x by w.

$$x^{2}+1x+28=7w+xw$$

Swap sides so that all variable terms are on the left hand side.

$$7w+xw=x^{2}+1x+28$$

Reorder the terms.

$$wx+7w=x^{2}+x+28$$

Combine all terms containing w.

$$\left(x+7\right)w=x^{2}+x+28$$

Divide both sides by 7+x.

$$\frac{\left(x+7\right)w}{x+7}=\frac{x^{2}+x+28}{x+7}$$

Dividing by 7+x undoes the multiplication by 7+x.

$$w=\frac{x^{2}+x+28}{x+7}$$

Solve for x (complex solution)

$$x=\frac{\sqrt{w^{2}+26w-111}+w-1}{2}$$

$$x=\frac{-\sqrt{w^{2}+26w-111}+w-1}{2}$$

Solve for x

$$x=\frac{\sqrt{w^{2}+26w-111}+w-1}{2}$$

$$x=\frac{-\sqrt{w^{2}+26w-111}+w-1}{2}\text{, }w\geq 2\sqrt{70}-13\text{ or }w\leq -2\sqrt{70}-13$$