Solve x^2+(-0,6)^2=1

$$x ^ { 2 } + ( - 0,6 ) ^ { 2 } = 1$$

Solve for x

$$x=0,8$$

$$x=-0,8$$

Steps Using Difference of Squares

Calculate -0,6 to the power of 2 and get 0,36.

$$x^{2}+0,36=1$$

Subtract 1 from both sides.

$$x^{2}+0,36-1=0$$

Subtract 1 from 0,36 to get -0,64.

$$x^{2}-0,64=0$$

Consider x^{2}-0,64. Rewrite x^{2}-0,64 as x^{2}-\left(\frac{4}{5}\right)^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(x-\frac{4}{5}\right)\left(x+\frac{4}{5}\right)=0$$

To find equation solutions, solve x-\frac{4}{5}=0 and x+\frac{4}{5}=0.

$$x=\frac{4}{5} x=-\frac{4}{5}$$

Steps by Finding Square Root

Calculate -0,6 to the power of 2 and get 0,36.

$$x^{2}+0,36=1$$

Subtract 0,36 from both sides.

$$x^{2}=1-0,36$$

Subtract 0,36 from 1 to get 0,64.

$$x^{2}=0,64$$

Take the square root of both sides of the equation.

$$x=\frac{4}{5} x=-\frac{4}{5}$$

Steps Using the Quadratic Formula

Calculate -0,6 to the power of 2 and get 0,36.

$$x^{2}+0,36=1$$

Subtract 1 from both sides.

$$x^{2}+0,36-1=0$$

Subtract 1 from 0,36 to get -0,64.

$$x^{2}-0,64=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -0,64 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-0,64\right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-0,64\right)}}{2}$$

Multiply -4 times -0,64.

$$x=\frac{0±\sqrt{2,56}}{2}$$

Take the square root of 2,56.

$$x=\frac{0±\frac{8}{5}}{2}$$

Now solve the equation x=\frac{0±\frac{8}{5}}{2} when ± is plus.

$$x=\frac{4}{5}$$

Now solve the equation x=\frac{0±\frac{8}{5}}{2} when ± is minus.

$$x=-\frac{4}{5}$$

The equation is now solved.

$$x=\frac{4}{5} x=-\frac{4}{5}$$