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Solve for x (complex solution)
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t^{2}-13t+36=0
Substitute t for x^{5}.
t=\frac{-\left(-13\right)±\sqrt{\left(-13\right)^{2}-4\times 1\times 36}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, -13 for b, and 36 for c in the quadratic formula.
t=\frac{13±5}{2}
Do the calculations.
t=9 t=4
Solve the equation t=\frac{13±5}{2} when ± is plus and when ± is minus.
x=-\sqrt[5]{9}ie^{\frac{\pi i}{10}} x=-\sqrt[5]{9}e^{\frac{\pi i}{5}} x=\sqrt[5]{9}ie^{\frac{3\pi i}{10}} x=\sqrt[5]{9}e^{\frac{2\pi i}{5}} x=\sqrt[5]{9} x=-\sqrt[5]{4}ie^{\frac{\pi i}{10}} x=-\sqrt[5]{4}e^{\frac{\pi i}{5}} x=\sqrt[5]{4}ie^{\frac{3\pi i}{10}} x=\sqrt[5]{4}e^{\frac{2\pi i}{5}} x=\sqrt[5]{4}
Since x=t^{5}, the solutions are obtained by solving the equation for each t.
t^{2}-13t+36=0
Substitute t for x^{5}.
t=\frac{-\left(-13\right)±\sqrt{\left(-13\right)^{2}-4\times 1\times 36}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, -13 for b, and 36 for c in the quadratic formula.
t=\frac{13±5}{2}
Do the calculations.
t=9 t=4
Solve the equation t=\frac{13±5}{2} when ± is plus and when ± is minus.
x=\sqrt[5]{9} x=\sqrt[5]{4}
Since x=t^{5}, the solutions are obtained by evaluating x=\sqrt[5]{t} for each t.