Solve x=6zquadx+6=

$$x = 6 z \quad x + 6 =$$

Solve for x

$$x=\frac{6}{1-6z}$$

$$z\neq \frac{1}{6}$$

Steps for Solving Linear Equation

Subtract 6zx from both sides.

$$x-6zx=6$$

Combine all terms containing x.

$$\left(1-6z\right)x=6$$

Divide both sides by -6z+1.

$$\frac{\left(1-6z\right)x}{1-6z}=\frac{6}{1-6z}$$

Dividing by -6z+1 undoes the multiplication by -6z+1.

$$x=\frac{6}{1-6z}$$

Solve for z

$$z=\frac{1}{6}-\frac{1}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$6zx+6=x$$

Subtract 6 from both sides.

$$6zx=x-6$$

The equation is in standard form.

$$6xz=x-6$$

Divide both sides by 6x.

$$\frac{6xz}{6x}=\frac{x-6}{6x}$$

Dividing by 6x undoes the multiplication by 6x.

$$z=\frac{x-6}{6x}$$

Divide x-6 by 6x.

$$z=\frac{1}{6}-\frac{1}{x}$$