Solve for k
k=-1+\frac{4}{x}
x\neq 0
Solve for x
x=\frac{4}{k+1}
k\neq -1
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4-kx=x
Swap sides so that all variable terms are on the left hand side.
-kx=x-4
Subtract 4 from both sides.
\left(-x\right)k=x-4
The equation is in standard form.
\frac{\left(-x\right)k}{-x}=\frac{x-4}{-x}
Divide both sides by -x.
k=\frac{x-4}{-x}
Dividing by -x undoes the multiplication by -x.
k=-1+\frac{4}{x}
Divide x-4 by -x.
x+kx=4
Add kx to both sides.
\left(1+k\right)x=4
Combine all terms containing x.
\left(k+1\right)x=4
The equation is in standard form.
\frac{\left(k+1\right)x}{k+1}=\frac{4}{k+1}
Divide both sides by 1+k.
x=\frac{4}{k+1}
Dividing by 1+k undoes the multiplication by 1+k.
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Limits
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