Solve x=(-1/3)^3+[3^-1-(-3)^-1]

$$x = ( - \frac { 1 } { 3 } ) ^ { 3 } + [ 3 ^ { - 1 } - ( - 3 ) ^ { - 1 } ]$$

Solve for x

$$x=\frac{17}{27}\approx 0.62962963$$

Steps for Solving Linear Equation

Calculate -\frac{1}{3} to the power of 3 and get -\frac{1}{27}.

$$x=-\frac{1}{27}+3^{-1}-\left(-3\right)^{-1}$$

Calculate 3 to the power of -1 and get \frac{1}{3}.

$$x=-\frac{1}{27}+\frac{1}{3}-\left(-3\right)^{-1}$$

Calculate -3 to the power of -1 and get -\frac{1}{3}.

$$x=-\frac{1}{27}+\frac{1}{3}-\left(-\frac{1}{3}\right)$$

The opposite of -\frac{1}{3} is \frac{1}{3}.

$$x=-\frac{1}{27}+\frac{1}{3}+\frac{1}{3}$$

Add \frac{1}{3} and \frac{1}{3} to get \frac{2}{3}.

$$x=-\frac{1}{27}+\frac{2}{3}$$

Add -\frac{1}{27} and \frac{2}{3} to get \frac{17}{27}.

$$x=\frac{17}{27}$$

Assign x

$$x≔\frac{17}{27}$$