Solve x=1/14+6/2-42/4=

$$x = \frac { 1 } { 14 } + \frac { 6 } { 2 } - \frac { 42 } { 4 } =$$

Solve for x

$$x = -\frac{52}{7} = -7\frac{3}{7} \approx -7.428571429$$

Steps for Solving Linear Equation

Divide 6 by 2 to get 3.

$$x=\frac{1}{14}+3-\frac{42}{4}$$

Convert 3 to fraction \frac{42}{14}.

$$x=\frac{1}{14}+\frac{42}{14}-\frac{42}{4}$$

Since \frac{1}{14} and \frac{42}{14} have the same denominator, add them by adding their numerators.

$$x=\frac{1+42}{14}-\frac{42}{4}$$

Add 1 and 42 to get 43.

$$x=\frac{43}{14}-\frac{42}{4}$$

Reduce the fraction \frac{42}{4} to lowest terms by extracting and canceling out 2.

$$x=\frac{43}{14}-\frac{21}{2}$$

Least common multiple of 14 and 2 is 14. Convert \frac{43}{14} and \frac{21}{2} to fractions with denominator 14.

$$x=\frac{43}{14}-\frac{147}{14}$$

Since \frac{43}{14} and \frac{147}{14} have the same denominator, subtract them by subtracting their numerators.

$$x=\frac{43-147}{14}$$

Subtract 147 from 43 to get -104.

$$x=\frac{-104}{14}$$

Reduce the fraction \frac{-104}{14} to lowest terms by extracting and canceling out 2.

$$x=-\frac{52}{7}$$

Assign x

$$x≔-\frac{52}{7}$$