Solve x=-2/3y-4

$$x = \frac { - 2 } { 3 } y - 4$$

Solve for y

$$y=-\frac{3x}{2}-6$$

Steps for Solving Linear Equation

Fraction \frac{-2}{3} can be rewritten as -\frac{2}{3} by extracting the negative sign.

$$x=-\frac{2}{3}y-4$$

Swap sides so that all variable terms are on the left hand side.

$$-\frac{2}{3}y-4=x$$

Add 4 to both sides.

$$-\frac{2}{3}y=x+4$$

Divide both sides of the equation by -\frac{2}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-\frac{2}{3}y}{-\frac{2}{3}}=\frac{x+4}{-\frac{2}{3}}$$

Dividing by -\frac{2}{3} undoes the multiplication by -\frac{2}{3}.

$$y=\frac{x+4}{-\frac{2}{3}}$$

Divide x+4 by -\frac{2}{3} by multiplying x+4 by the reciprocal of -\frac{2}{3}.

$$y=-\frac{3x}{2}-6$$

Solve for x

$$x=-\frac{2y}{3}-4$$

Solution Steps

Fraction \frac{-2}{3} can be rewritten as -\frac{2}{3} by extracting the negative sign.

$$x=-\frac{2}{3}y-4$$