Solve x=4y+2x^2

$$x = 4y+2 { x }^{ 2 }$$

Solve for y

$$y=\frac{x\left(1-2x\right)}{4}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$4y+2x^{2}=x$$

Subtract 2x^{2} from both sides.

$$4y=x-2x^{2}$$

Divide both sides by 4.

$$\frac{4y}{4}=\frac{x\left(1-2x\right)}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$y=\frac{x\left(1-2x\right)}{4}$$

Solve for x (complex solution)

$$x=\frac{-\sqrt{1-32y}+1}{4}$$

$$x=\frac{\sqrt{1-32y}+1}{4}$$

Solve for x

$$x=\frac{-\sqrt{1-32y}+1}{4}$$

$$x=\frac{\sqrt{1-32y}+1}{4}\text{, }y\leq \frac{1}{32}$$