Solve for y
y=\frac{\sqrt{\frac{\pi }{\theta _{2}}}x^{3}}{|x|}
x\neq 0\text{ and }\theta _{2}>0
Solve for x
\left\{\begin{matrix}x=\sqrt[4]{\frac{\theta _{2}}{\pi }}\sqrt{y}\text{, }&y>0\text{ and }\theta _{2}>0\\x=-\sqrt[4]{\frac{\theta _{2}}{\pi }}\sqrt{-y}\text{, }&\theta _{2}>0\text{ and }y<0\end{matrix}\right.
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xx^{2}=y\sqrt{\frac{x}{\frac{\pi }{\theta _{2}x}}}
Multiply both sides of the equation by x^{2}.
x^{3}=y\sqrt{\frac{x}{\frac{\pi }{\theta _{2}x}}}
To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.
x^{3}=y\sqrt{\frac{x\theta _{2}x}{\pi }}
Divide x by \frac{\pi }{\theta _{2}x} by multiplying x by the reciprocal of \frac{\pi }{\theta _{2}x}.
x^{3}=y\sqrt{\frac{x^{2}\theta _{2}}{\pi }}
Multiply x and x to get x^{2}.
y\sqrt{\frac{x^{2}\theta _{2}}{\pi }}=x^{3}
Swap sides so that all variable terms are on the left hand side.
\sqrt{\frac{\theta _{2}x^{2}}{\pi }}y=x^{3}
The equation is in standard form.
\frac{\sqrt{\frac{\theta _{2}x^{2}}{\pi }}y}{\sqrt{\frac{\theta _{2}x^{2}}{\pi }}}=\frac{x^{3}}{\sqrt{\frac{\theta _{2}x^{2}}{\pi }}}
Divide both sides by \sqrt{x^{2}\theta _{2}\pi ^{-1}}.
y=\frac{x^{3}}{\sqrt{\frac{\theta _{2}x^{2}}{\pi }}}
Dividing by \sqrt{x^{2}\theta _{2}\pi ^{-1}} undoes the multiplication by \sqrt{x^{2}\theta _{2}\pi ^{-1}}.
y=\frac{\sqrt{\pi }x^{3}}{\sqrt{\theta _{2}}|x|}
Divide x^{3} by \sqrt{x^{2}\theta _{2}\pi ^{-1}}.
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