Solve for x
x=\frac{3}{4}=0.75
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x≔\frac{3}{4}
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x=\frac{\frac{1}{2}-\frac{7\left(-1\right)}{4}}{3}
Express 7\left(-\frac{1}{4}\right) as a single fraction.
x=\frac{\frac{1}{2}-\frac{-7}{4}}{3}
Multiply 7 and -1 to get -7.
x=\frac{\frac{1}{2}-\left(-\frac{7}{4}\right)}{3}
Fraction \frac{-7}{4} can be rewritten as -\frac{7}{4} by extracting the negative sign.
x=\frac{\frac{1}{2}+\frac{7}{4}}{3}
The opposite of -\frac{7}{4} is \frac{7}{4}.
x=\frac{\frac{2}{4}+\frac{7}{4}}{3}
Least common multiple of 2 and 4 is 4. Convert \frac{1}{2} and \frac{7}{4} to fractions with denominator 4.
x=\frac{\frac{2+7}{4}}{3}
Since \frac{2}{4} and \frac{7}{4} have the same denominator, add them by adding their numerators.
x=\frac{\frac{9}{4}}{3}
Add 2 and 7 to get 9.
x=\frac{9}{4\times 3}
Express \frac{\frac{9}{4}}{3} as a single fraction.
x=\frac{9}{12}
Multiply 4 and 3 to get 12.
x=\frac{3}{4}
Reduce the fraction \frac{9}{12} to lowest terms by extracting and canceling out 3.
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