Solve x+9-3+4-1+8-1=

$$x + 9 - 3 + 4 - 1 + 8 - 1 =$$

Evaluate

$$x+16$$

Solution Steps

Subtract 3 from 9 to get 6.

$$x+6+4-1+8-1$$

Add 6 and 4 to get 10.

$$x+10-1+8-1$$

Subtract 1 from 10 to get 9.

$$x+9+8-1$$

Add 9 and 8 to get 17.

$$x+17-1$$

Subtract 1 from 17 to get 16.

$$x+16$$

Differentiate w.r.t. x

$$1$$

Steps Using Derivative Rule for Sum

Subtract 3 from 9 to get 6.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x+6+4-1+8-1)$$

Add 6 and 4 to get 10.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x+10-1+8-1)$$

Subtract 1 from 10 to get 9.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x+9+8-1)$$

Add 9 and 8 to get 17.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x+17-1)$$

Subtract 1 from 17 to get 16.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x+16)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$x^{1-1}$$

Subtract 1 from 1.

$$x^{0}$$

For any term t except 0, t^{0}=1.

$$1$$