Solve for x
x=7-3y
Solve for y
y=\frac{7-x}{3}
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x-7=-3y
Subtract 3y from both sides. Anything subtracted from zero gives its negation.
x=-3y+7
Add 7 to both sides.
3y-7=-x
Subtract x from both sides. Anything subtracted from zero gives its negation.
3y=-x+7
Add 7 to both sides.
3y=7-x
The equation is in standard form.
\frac{3y}{3}=\frac{7-x}{3}
Divide both sides by 3.
y=\frac{7-x}{3}
Dividing by 3 undoes the multiplication by 3.
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