Solve for x
x\geq 0
Solve for z
z\in \mathrm{R}
x\geq 0
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x+2y-z+x\geq 2y-z
Add x to both sides.
2x+2y-z\geq 2y-z
Combine x and x to get 2x.
2x-z\geq 2y-z-2y
Subtract 2y from both sides.
2x-z\geq -z
Combine 2y and -2y to get 0.
2x\geq -z+z
Add z to both sides.
2x\geq 0
Combine -z and z to get 0.
x\geq 0
Product of two numbers is ≥0 if both are ≥0 or both are ≤0. Since 2\geq 0, x must be ≥0.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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