Solve x+2*(1-5m/3)=1-m

$$x + 2 \cdot ( \frac { 1 - 5 m } { 3 } ) = 1 - m$$

Solve for m

$$m=\frac{3x-1}{7}$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 3.

$$3x+2\left(1-5m\right)=3-3m$$

Use the distributive property to multiply 2 by 1-5m.

$$3x+2-10m=3-3m$$

Add 3m to both sides.

$$3x+2-10m+3m=3$$

Combine -10m and 3m to get -7m.

$$3x+2-7m=3$$

Subtract 3x from both sides.

$$2-7m=3-3x$$

Subtract 2 from both sides.

$$-7m=3-3x-2$$

Subtract 2 from 3 to get 1.

$$-7m=1-3x$$

Divide both sides by -7.

$$\frac{-7m}{-7}=\frac{1-3x}{-7}$$

Dividing by -7 undoes the multiplication by -7.

$$m=\frac{1-3x}{-7}$$

Divide 1-3x by -7.

$$m=\frac{3x-1}{7}$$

Solve for x

$$x=\frac{7m+1}{3}$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 3.

$$3x+2\left(1-5m\right)=3-3m$$

Use the distributive property to multiply 2 by 1-5m.

$$3x+2-10m=3-3m$$

Subtract 2 from both sides.

$$3x-10m=3-3m-2$$

Subtract 2 from 3 to get 1.

$$3x-10m=1-3m$$

Add 10m to both sides.

$$3x=1-3m+10m$$

Combine -3m and 10m to get 7m.

$$3x=1+7m$$

The equation is in standard form.

$$3x=7m+1$$

Divide both sides by 3.

$$\frac{3x}{3}=\frac{7m+1}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$x=\frac{7m+1}{3}$$