Solve for x
x=210-2z-3y
Solve for y
y=-\frac{x}{3}-\frac{2z}{3}+70
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x+5+2z=215-3y
Subtract 3y from both sides.
x+2z=215-3y-5
Subtract 5 from both sides.
x+2z=210-3y
Subtract 5 from 215 to get 210.
x=210-3y-2z
Subtract 2z from both sides.
3y+5+2z=215-x
Subtract x from both sides.
3y+2z=215-x-5
Subtract 5 from both sides.
3y+2z=210-x
Subtract 5 from 215 to get 210.
3y=210-x-2z
Subtract 2z from both sides.
3y=210-2z-x
The equation is in standard form.
\frac{3y}{3}=\frac{210-2z-x}{3}
Divide both sides by 3.
y=\frac{210-2z-x}{3}
Dividing by 3 undoes the multiplication by 3.
y=-\frac{x}{3}-\frac{2z}{3}+70
Divide 210-x-2z by 3.
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