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3x+\sqrt{5}+6=240
Multiply both sides of the equation by 3.
3x+6=240-\sqrt{5}
Subtract \sqrt{5} from both sides.
3x=240-\sqrt{5}-6
Subtract 6 from both sides.
3x=234-\sqrt{5}
Subtract 6 from 240 to get 234.
\frac{3x}{3}=\frac{234-\sqrt{5}}{3}
Divide both sides by 3.
x=\frac{234-\sqrt{5}}{3}
Dividing by 3 undoes the multiplication by 3.
x=-\frac{\sqrt{5}}{3}+78
Divide 234-\sqrt{5} by 3.