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\left(2r+w^{2}\right)\left(4r^{2}-2rw^{2}+w^{4}\right)
Rewrite w^{6}+8r^{3} as \left(2r\right)^{3}+\left(w^{2}\right)^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right).