Solve w^2-3x-18=0

$$w ^ { 2 } - 3 x - 18 = 0$$

Solve for x

$$x=\frac{w^{2}-18}{3}$$

Steps for Solving Linear Equation

Subtract w^{2} from both sides. Anything subtracted from zero gives its negation.

$$-3x-18=-w^{2}$$

Add 18 to both sides.

$$-3x=-w^{2}+18$$

The equation is in standard form.

$$-3x=18-w^{2}$$

Divide both sides by -3.

$$\frac{-3x}{-3}=\frac{18-w^{2}}{-3}$$

Dividing by -3 undoes the multiplication by -3.

$$x=\frac{18-w^{2}}{-3}$$

Divide -w^{2}+18 by -3.

$$x=\frac{w^{2}}{3}-6$$

Solve for w (complex solution)

$$w=-\sqrt{3\left(x+6\right)}$$

$$w=\sqrt{3\left(x+6\right)}$$

Solve for w

$$w=\sqrt{3\left(x+6\right)}$$

$$w=-\sqrt{3\left(x+6\right)}\text{, }x\geq -6$$