Factor
\left(w-6\right)\left(w+4\right)
Evaluate
\left(w-6\right)\left(w+4\right)
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a+b=-2 ab=1\left(-24\right)=-24
Factor the expression by grouping. First, the expression needs to be rewritten as w^{2}+aw+bw-24. To find a and b, set up a system to be solved.
1,-24 2,-12 3,-8 4,-6
Since ab is negative, a and b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. List all such integer pairs that give product -24.
1-24=-23 2-12=-10 3-8=-5 4-6=-2
Calculate the sum for each pair.
a=-6 b=4
The solution is the pair that gives sum -2.
\left(w^{2}-6w\right)+\left(4w-24\right)
Rewrite w^{2}-2w-24 as \left(w^{2}-6w\right)+\left(4w-24\right).
w\left(w-6\right)+4\left(w-6\right)
Factor out w in the first and 4 in the second group.
\left(w-6\right)\left(w+4\right)
Factor out common term w-6 by using distributive property.
w^{2}-2w-24=0
Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.
w=\frac{-\left(-2\right)±\sqrt{\left(-2\right)^{2}-4\left(-24\right)}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
w=\frac{-\left(-2\right)±\sqrt{4-4\left(-24\right)}}{2}
Square -2.
w=\frac{-\left(-2\right)±\sqrt{4+96}}{2}
Multiply -4 times -24.
w=\frac{-\left(-2\right)±\sqrt{100}}{2}
Add 4 to 96.
w=\frac{-\left(-2\right)±10}{2}
Take the square root of 100.
w=\frac{2±10}{2}
The opposite of -2 is 2.
w=\frac{12}{2}
Now solve the equation w=\frac{2±10}{2} when ± is plus. Add 2 to 10.
w=6
Divide 12 by 2.
w=-\frac{8}{2}
Now solve the equation w=\frac{2±10}{2} when ± is minus. Subtract 10 from 2.
w=-4
Divide -8 by 2.
w^{2}-2w-24=\left(w-6\right)\left(w-\left(-4\right)\right)
Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute 6 for x_{1} and -4 for x_{2}.
w^{2}-2w-24=\left(w-6\right)\left(w+4\right)
Simplify all the expressions of the form p-\left(-q\right) to p+q.
x ^ 2 -2x -24 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = 2 rs = -24
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = 1 - u s = 1 + u
Two numbers r and s sum up to 2 exactly when the average of the two numbers is \frac{1}{2}*2 = 1. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(1 - u) (1 + u) = -24
To solve for unknown quantity u, substitute these in the product equation rs = -24
1 - u^2 = -24
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = -24-1 = -25
Simplify the expression by subtracting 1 on both sides
u^2 = 25 u = \pm\sqrt{25} = \pm 5
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =1 - 5 = -4 s = 1 + 5 = 6
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.
Examples
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{ x } ^ { 2 } - 4 x - 5 = 0
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4 \sin \theta \cos \theta = 2 \sin \theta
Linear equation
y = 3x + 4
Arithmetic
699 * 533
Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}