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w^{2}+14w+136=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
w=\frac{-14±\sqrt{14^{2}-4\times 136}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 14 for b, and 136 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
w=\frac{-14±\sqrt{196-4\times 136}}{2}
Square 14.
w=\frac{-14±\sqrt{196-544}}{2}
Multiply -4 times 136.
w=\frac{-14±\sqrt{-348}}{2}
Add 196 to -544.
w=\frac{-14±2\sqrt{87}i}{2}
Take the square root of -348.
w=\frac{-14+2\sqrt{87}i}{2}
Now solve the equation w=\frac{-14±2\sqrt{87}i}{2} when ± is plus. Add -14 to 2i\sqrt{87}.
w=-7+\sqrt{87}i
Divide -14+2i\sqrt{87} by 2.
w=\frac{-2\sqrt{87}i-14}{2}
Now solve the equation w=\frac{-14±2\sqrt{87}i}{2} when ± is minus. Subtract 2i\sqrt{87} from -14.
w=-\sqrt{87}i-7
Divide -14-2i\sqrt{87} by 2.
w=-7+\sqrt{87}i w=-\sqrt{87}i-7
The equation is now solved.
w^{2}+14w+136=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
w^{2}+14w+136-136=-136
Subtract 136 from both sides of the equation.
w^{2}+14w=-136
Subtracting 136 from itself leaves 0.
w^{2}+14w+7^{2}=-136+7^{2}
Divide 14, the coefficient of the x term, by 2 to get 7. Then add the square of 7 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
w^{2}+14w+49=-136+49
Square 7.
w^{2}+14w+49=-87
Add -136 to 49.
\left(w+7\right)^{2}=-87
Factor w^{2}+14w+49. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(w+7\right)^{2}}=\sqrt{-87}
Take the square root of both sides of the equation.
w+7=\sqrt{87}i w+7=-\sqrt{87}i
Simplify.
w=-7+\sqrt{87}i w=-\sqrt{87}i-7
Subtract 7 from both sides of the equation.
x ^ 2 +14x +136 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = -14 rs = 136
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = -7 - u s = -7 + u
Two numbers r and s sum up to -14 exactly when the average of the two numbers is \frac{1}{2}*-14 = -7. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(-7 - u) (-7 + u) = 136
To solve for unknown quantity u, substitute these in the product equation rs = 136
49 - u^2 = 136
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = 136-49 = 87
Simplify the expression by subtracting 49 on both sides
u^2 = -87 u = \pm\sqrt{-87} = \pm \sqrt{87}i
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =-7 - \sqrt{87}i s = -7 + \sqrt{87}i
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.