Solve for w
w=5
w=4
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w^{2}=\left(\sqrt{9w-20}\right)^{2}
Square both sides of the equation.
w^{2}=9w-20
Calculate \sqrt{9w-20} to the power of 2 and get 9w-20.
w^{2}-9w=-20
Subtract 9w from both sides.
w^{2}-9w+20=0
Add 20 to both sides.
a+b=-9 ab=20
To solve the equation, factor w^{2}-9w+20 using formula w^{2}+\left(a+b\right)w+ab=\left(w+a\right)\left(w+b\right). To find a and b, set up a system to be solved.
-1,-20 -2,-10 -4,-5
Since ab is positive, a and b have the same sign. Since a+b is negative, a and b are both negative. List all such integer pairs that give product 20.
-1-20=-21 -2-10=-12 -4-5=-9
Calculate the sum for each pair.
a=-5 b=-4
The solution is the pair that gives sum -9.
\left(w-5\right)\left(w-4\right)
Rewrite factored expression \left(w+a\right)\left(w+b\right) using the obtained values.
w=5 w=4
To find equation solutions, solve w-5=0 and w-4=0.
5=\sqrt{9\times 5-20}
Substitute 5 for w in the equation w=\sqrt{9w-20}.
5=5
Simplify. The value w=5 satisfies the equation.
4=\sqrt{9\times 4-20}
Substitute 4 for w in the equation w=\sqrt{9w-20}.
4=4
Simplify. The value w=4 satisfies the equation.
w=5 w=4
List all solutions of w=\sqrt{9w-20}.
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