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Solve for d
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duxu+uxdy=duxu+dx
Variable d cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by dux, the least common multiple of dx,u.
du^{2}x+uxdy=duxu+dx
Multiply u and u to get u^{2}.
du^{2}x+uxdy=du^{2}x+dx
Multiply u and u to get u^{2}.
du^{2}x+uxdy-du^{2}x=dx
Subtract du^{2}x from both sides.
uxdy=dx
Combine du^{2}x and -du^{2}x to get 0.
uxdy-dx=0
Subtract dx from both sides.
\left(uxy-x\right)d=0
Combine all terms containing d.
d=0
Divide 0 by uxy-x.
d\in \emptyset
Variable d cannot be equal to 0.
duxu+uxdy=duxu+dx
Variable u cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by dux, the least common multiple of dx,u.
du^{2}x+uxdy=duxu+dx
Multiply u and u to get u^{2}.
du^{2}x+uxdy=du^{2}x+dx
Multiply u and u to get u^{2}.
du^{2}x+uxdy-du^{2}x=dx
Subtract du^{2}x from both sides.
uxdy=dx
Combine du^{2}x and -du^{2}x to get 0.
dxyu=dx
The equation is in standard form.
\frac{dxyu}{dxy}=\frac{dx}{dxy}
Divide both sides by xdy.
u=\frac{dx}{dxy}
Dividing by xdy undoes the multiplication by xdy.
u=\frac{1}{y}
Divide dx by xdy.
u=\frac{1}{y}\text{, }u\neq 0
Variable u cannot be equal to 0.