Solve t^2-4t+65=t^2-8t+41

$$t ^ { 2 } - 4 t + 65 = t ^ { 2 } - 8 t + 41$$

Solve for t

$$t=-6$$

Steps for Solving Linear Equation

Subtract t^{2} from both sides.

$$t^{2}-4t+65-t^{2}=-8t+41$$

Combine t^{2} and -t^{2} to get 0.

$$-4t+65=-8t+41$$

Add 8t to both sides.

$$-4t+65+8t=41$$

Combine -4t and 8t to get 4t.

$$4t+65=41$$

Subtract 65 from both sides.

$$4t=41-65$$

Subtract 65 from 41 to get -24.

$$4t=-24$$

Divide both sides by 4.

$$t=\frac{-24}{4}$$

Divide -24 by 4 to get -6.

$$t=-6$$