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t\left(t-21\right)=0
Factor out t.
t=0 t=21
To find equation solutions, solve t=0 and t-21=0.
t^{2}-21t=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
t=\frac{-\left(-21\right)±\sqrt{\left(-21\right)^{2}}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -21 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
t=\frac{-\left(-21\right)±21}{2}
Take the square root of \left(-21\right)^{2}.
t=\frac{21±21}{2}
The opposite of -21 is 21.
t=\frac{42}{2}
Now solve the equation t=\frac{21±21}{2} when ± is plus. Add 21 to 21.
t=21
Divide 42 by 2.
t=\frac{0}{2}
Now solve the equation t=\frac{21±21}{2} when ± is minus. Subtract 21 from 21.
t=0
Divide 0 by 2.
t=21 t=0
The equation is now solved.
t^{2}-21t=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
t^{2}-21t+\left(-\frac{21}{2}\right)^{2}=\left(-\frac{21}{2}\right)^{2}
Divide -21, the coefficient of the x term, by 2 to get -\frac{21}{2}. Then add the square of -\frac{21}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
t^{2}-21t+\frac{441}{4}=\frac{441}{4}
Square -\frac{21}{2} by squaring both the numerator and the denominator of the fraction.
\left(t-\frac{21}{2}\right)^{2}=\frac{441}{4}
Factor t^{2}-21t+\frac{441}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(t-\frac{21}{2}\right)^{2}}=\sqrt{\frac{441}{4}}
Take the square root of both sides of the equation.
t-\frac{21}{2}=\frac{21}{2} t-\frac{21}{2}=-\frac{21}{2}
Simplify.
t=21 t=0
Add \frac{21}{2} to both sides of the equation.