Solve t^2-2x-3=0

$$t ^ { 2 } - 2 x - 3 = 0$$

Solve for x

$$x=\frac{t^{2}-3}{2}$$

Steps for Solving Linear Equation

Subtract t^{2} from both sides. Anything subtracted from zero gives its negation.

$$-2x-3=-t^{2}$$

Add 3 to both sides.

$$-2x=-t^{2}+3$$

The equation is in standard form.

$$-2x=3-t^{2}$$

Divide both sides by -2.

$$\frac{-2x}{-2}=\frac{3-t^{2}}{-2}$$

Dividing by -2 undoes the multiplication by -2.

$$x=\frac{3-t^{2}}{-2}$$

Divide -t^{2}+3 by -2.

$$x=\frac{t^{2}-3}{2}$$

Solve for t (complex solution)

$$t=-\sqrt{2x+3}$$

$$t=\sqrt{2x+3}$$

Solve for t

$$t=\sqrt{2x+3}$$

$$t=-\sqrt{2x+3}\text{, }x\geq -\frac{3}{2}$$