Solve t^2-2t+2=t^2-8t+20

$$t ^ { 2 } - 2 t + 2 = t ^ { 2 } - 8 t + 20$$

Solve for t

$$t=3$$

Steps for Solving Linear Equation

Subtract t^{2} from both sides.

$$t^{2}-2t+2-t^{2}=-8t+20$$

Combine t^{2} and -t^{2} to get 0.

$$-2t+2=-8t+20$$

Add 8t to both sides.

$$-2t+2+8t=20$$

Combine -2t and 8t to get 6t.

$$6t+2=20$$

Subtract 2 from both sides.

$$6t=20-2$$

Subtract 2 from 20 to get 18.

$$6t=18$$

Divide both sides by 6.

$$t=\frac{18}{6}$$

Divide 18 by 6 to get 3.

$$t=3$$