Solve t^2-2-4t+520

$$t ^ { 2 } - 2 - 4 t + 520$$

Differentiate w.r.t. t

$$2\left(t-2\right)$$

Steps Using Derivative Rule for Sum

Add -2 and 520 to get 518.

$$\frac{\mathrm{d}}{\mathrm{d}t}(t^{2}+518-4t)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$2t^{2-1}-4t^{1-1}$$

Subtract 1 from 2.

$$2t^{1}-4t^{1-1}$$

Subtract 1 from 1.

$$2t^{1}-4t^{0}$$

For any term t, t^{1}=t.

$$2t-4t^{0}$$

For any term t except 0, t^{0}=1.

$$2t-4$$

Evaluate

$$t^{2}-4t+518$$

Solution Steps

Add -2 and 520 to get 518.

$$t^{2}+518-4t$$