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t^{2}-190t+900=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
t=\frac{-\left(-190\right)±\sqrt{\left(-190\right)^{2}-4\times 900}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -190 for b, and 900 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
t=\frac{-\left(-190\right)±\sqrt{36100-4\times 900}}{2}
Square -190.
t=\frac{-\left(-190\right)±\sqrt{36100-3600}}{2}
Multiply -4 times 900.
t=\frac{-\left(-190\right)±\sqrt{32500}}{2}
Add 36100 to -3600.
t=\frac{-\left(-190\right)±50\sqrt{13}}{2}
Take the square root of 32500.
t=\frac{190±50\sqrt{13}}{2}
The opposite of -190 is 190.
t=\frac{50\sqrt{13}+190}{2}
Now solve the equation t=\frac{190±50\sqrt{13}}{2} when ± is plus. Add 190 to 50\sqrt{13}.
t=25\sqrt{13}+95
Divide 190+50\sqrt{13} by 2.
t=\frac{190-50\sqrt{13}}{2}
Now solve the equation t=\frac{190±50\sqrt{13}}{2} when ± is minus. Subtract 50\sqrt{13} from 190.
t=95-25\sqrt{13}
Divide 190-50\sqrt{13} by 2.
t=25\sqrt{13}+95 t=95-25\sqrt{13}
The equation is now solved.
t^{2}-190t+900=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
t^{2}-190t+900-900=-900
Subtract 900 from both sides of the equation.
t^{2}-190t=-900
Subtracting 900 from itself leaves 0.
t^{2}-190t+\left(-95\right)^{2}=-900+\left(-95\right)^{2}
Divide -190, the coefficient of the x term, by 2 to get -95. Then add the square of -95 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
t^{2}-190t+9025=-900+9025
Square -95.
t^{2}-190t+9025=8125
Add -900 to 9025.
\left(t-95\right)^{2}=8125
Factor t^{2}-190t+9025. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(t-95\right)^{2}}=\sqrt{8125}
Take the square root of both sides of the equation.
t-95=25\sqrt{13} t-95=-25\sqrt{13}
Simplify.
t=25\sqrt{13}+95 t=95-25\sqrt{13}
Add 95 to both sides of the equation.
x ^ 2 -190x +900 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = 190 rs = 900
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = 95 - u s = 95 + u
Two numbers r and s sum up to 190 exactly when the average of the two numbers is \frac{1}{2}*190 = 95. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(95 - u) (95 + u) = 900
To solve for unknown quantity u, substitute these in the product equation rs = 900
9025 - u^2 = 900
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = 900-9025 = -8125
Simplify the expression by subtracting 9025 on both sides
u^2 = 8125 u = \pm\sqrt{8125} = \pm \sqrt{8125}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =95 - \sqrt{8125} = 4.861 s = 95 + \sqrt{8125} = 185.139
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.