Solve t^2*2^-5

$$t ^ { 2 } \cdot 2 ^ { - 5 }$$

Differentiate w.r.t. t

$$\frac{t}{16}$$

Steps Using Definition of a Derivative

Calculate 2 to the power of -5 and get \frac{1}{32}.

$$\frac{\mathrm{d}}{\mathrm{d}t}(t^{2}\times \frac{1}{32})$$

The derivative of ax^{n} is nax^{n-1}.

$$2\times \frac{1}{32}t^{2-1}$$

Multiply 2 times \frac{1}{32}.

$$\frac{1}{16}t^{2-1}$$

Subtract 1 from 2.

$$\frac{1}{16}t^{1}$$

For any term t, t^{1}=t.

$$\frac{1}{16}t$$

Evaluate

$$\frac{t^{2}}{32}$$

Solution Steps

Calculate 2 to the power of -5 and get \frac{1}{32}.

$$t^{2}\times \frac{1}{32}$$