Solve t^2=2p+as

$$t ^ { 2 } = 2 p + a s$$

Solve for a

$$\left\{\begin{matrix}a=\frac{t^{2}-2p}{s}\text{, }&s\neq 0\\a\in \mathrm{R}\text{, }&p=\frac{t^{2}}{2}\text{ and }s=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$2p+as=t^{2}$$

Subtract 2p from both sides.

$$as=t^{2}-2p$$

The equation is in standard form.

$$sa=t^{2}-2p$$

Divide both sides by s.

$$\frac{sa}{s}=\frac{t^{2}-2p}{s}$$

Dividing by s undoes the multiplication by s.

$$a=\frac{t^{2}-2p}{s}$$

Solve for p

$$p=\frac{t^{2}-as}{2}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$2p+as=t^{2}$$

Subtract as from both sides.

$$2p=t^{2}-as$$

Divide both sides by 2.

$$\frac{2p}{2}=\frac{t^{2}-as}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$p=\frac{t^{2}-as}{2}$$