Solve for h (complex solution)
\left\{\begin{matrix}h=\frac{-xy+\epsilon -t}{x}\text{, }&x\neq 0\\h\in \mathrm{C}\text{, }&t=\epsilon \text{ and }x=0\end{matrix}\right.
Solve for h
\left\{\begin{matrix}h=\frac{-xy+\epsilon -t}{x}\text{, }&x\neq 0\\h\in \mathrm{R}\text{, }&t=\epsilon \text{ and }x=0\end{matrix}\right.
Solve for t
t=\epsilon -xy-hx
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\epsilon -xh=t+xy
Swap sides so that all variable terms are on the left hand side.
-xh=t+xy-\epsilon
Subtract \epsilon from both sides.
\left(-x\right)h=xy+t-\epsilon
The equation is in standard form.
\frac{\left(-x\right)h}{-x}=\frac{xy+t-\epsilon }{-x}
Divide both sides by -x.
h=\frac{xy+t-\epsilon }{-x}
Dividing by -x undoes the multiplication by -x.
h=-\frac{xy+t-\epsilon }{x}
Divide t+xy-\epsilon by -x.
\epsilon -xh=t+xy
Swap sides so that all variable terms are on the left hand side.
-xh=t+xy-\epsilon
Subtract \epsilon from both sides.
\left(-x\right)h=xy+t-\epsilon
The equation is in standard form.
\frac{\left(-x\right)h}{-x}=\frac{xy+t-\epsilon }{-x}
Divide both sides by -x.
h=\frac{xy+t-\epsilon }{-x}
Dividing by -x undoes the multiplication by -x.
h=-\frac{xy+t-\epsilon }{x}
Divide t+xy-\epsilon by -x.
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