Solve s-(x-3)-5(x-5)=-4

$$s - ( x - 3 ) - 5 ( x - 5 ) = - 4$$

Solve for s

$$s=6x-32$$

Solution Steps

To find the opposite of x-3, find the opposite of each term.

$$s-x+3-5\left(x-5\right)=-4$$

Use the distributive property to multiply -5 by x-5.

$$s-x+3-5x+25=-4$$

Combine -x and -5x to get -6x.

$$s-6x+3+25=-4$$

Add 3 and 25 to get 28.

$$s-6x+28=-4$$

Add 6x to both sides.

$$s+28=-4+6x$$

Subtract 28 from both sides.

$$s=-4+6x-28$$

Subtract 28 from -4 to get -32.

$$s=-32+6x$$

Solve for x

$$x=\frac{s+32}{6}$$

Steps for Solving Linear Equation

To find the opposite of x-3, find the opposite of each term.

$$s-x+3-5\left(x-5\right)=-4$$

Use the distributive property to multiply -5 by x-5.

$$s-x+3-5x+25=-4$$

Combine -x and -5x to get -6x.

$$s-6x+3+25=-4$$

Add 3 and 25 to get 28.

$$s-6x+28=-4$$

Subtract s from both sides.

$$-6x+28=-4-s$$

Subtract 28 from both sides.

$$-6x=-4-s-28$$

Subtract 28 from -4 to get -32.

$$-6x=-32-s$$

The equation is in standard form.

$$-6x=-s-32$$

Divide both sides by -6.

$$\frac{-6x}{-6}=\frac{-s-32}{-6}$$

Dividing by -6 undoes the multiplication by -6.

$$x=\frac{-s-32}{-6}$$

Divide -32-s by -6.

$$x=\frac{s}{6}+\frac{16}{3}$$