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r^{2}=15
Add 15 to both sides. Anything plus zero gives itself.
r=\sqrt{15} r=-\sqrt{15}
Take the square root of both sides of the equation.
r^{2}-15=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
r=\frac{0±\sqrt{0^{2}-4\left(-15\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -15 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
r=\frac{0±\sqrt{-4\left(-15\right)}}{2}
Square 0.
r=\frac{0±\sqrt{60}}{2}
Multiply -4 times -15.
r=\frac{0±2\sqrt{15}}{2}
Take the square root of 60.
r=\sqrt{15}
Now solve the equation r=\frac{0±2\sqrt{15}}{2} when ± is plus.
r=-\sqrt{15}
Now solve the equation r=\frac{0±2\sqrt{15}}{2} when ± is minus.
r=\sqrt{15} r=-\sqrt{15}
The equation is now solved.