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r^{2}-441=0
Subtract 441 from both sides.
\left(r-21\right)\left(r+21\right)=0
Consider r^{2}-441. Rewrite r^{2}-441 as r^{2}-21^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
r=21 r=-21
To find equation solutions, solve r-21=0 and r+21=0.
r=21 r=-21
Take the square root of both sides of the equation.
r^{2}-441=0
Subtract 441 from both sides.
r=\frac{0±\sqrt{0^{2}-4\left(-441\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -441 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
r=\frac{0±\sqrt{-4\left(-441\right)}}{2}
Square 0.
r=\frac{0±\sqrt{1764}}{2}
Multiply -4 times -441.
r=\frac{0±42}{2}
Take the square root of 1764.
r=21
Now solve the equation r=\frac{0±42}{2} when ± is plus. Divide 42 by 2.
r=-21
Now solve the equation r=\frac{0±42}{2} when ± is minus. Divide -42 by 2.
r=21 r=-21
The equation is now solved.