Solve r^prime(x)=4+4cosx/1+cos2x:operatorname{mox}

$$r ^ { \prime } ( x ) = \frac { 4 + 4 \cos x } { 1 + \cos 2 x } : \operatorname { mox }$$

Solve for m

$$m\neq 0$$

$$\left(\exists n_{1}\in \mathrm{Z}\text{ : }\left(x>\pi n_{1}+\frac{\pi }{2}\text{ and }x<\pi n_{1}+\frac{3\pi }{2}\right)\text{ and }o=0\right)\text{ or }\exists n_{2}\in \mathrm{Z}\text{ : }x=2\pi n_{2}+\pi \text{ or }x=0$$

Steps for Solving Linear Equation

Variable m cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by m.

$$\frac{\mathrm{d}}{\mathrm{d}x}(r)xm=\frac{4+4\cos(x)}{1+\cos(2x)}ox$$

Express \frac{4+4\cos(x)}{1+\cos(2x)}o as a single fraction.

$$\frac{\mathrm{d}}{\mathrm{d}x}(r)xm=\frac{\left(4+4\cos(x)\right)o}{1+\cos(2x)}x$$

Express \frac{\left(4+4\cos(x)\right)o}{1+\cos(2x)}x as a single fraction.

$$\frac{\mathrm{d}}{\mathrm{d}x}(r)xm=\frac{\left(4+4\cos(x)\right)ox}{1+\cos(2x)}$$

Use the distributive property to multiply 4+4\cos(x) by o.

$$\frac{\mathrm{d}}{\mathrm{d}x}(r)xm=\frac{\left(4o+4\cos(x)o\right)x}{1+\cos(2x)}$$

Use the distributive property to multiply 4o+4\cos(x)o by x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(r)xm=\frac{4ox+4\cos(x)ox}{1+\cos(2x)}$$

The equation is in standard form.

$$0=\frac{4ox\cos(x)+4ox}{\cos(2x)+1}$$

This is false for any m.

$$m\in$$

Solve for o

$$\left\{\begin{matrix}o=0\text{, }&\nexists n_{1}\in \mathrm{Z}\text{ : }x=\pi n_{1}+\frac{\pi }{2}\text{ and }m\neq 0\\o\in \mathrm{R}\text{, }&\left(x=0\text{ and }m\neq 0\right)\text{ or }\left(\exists n_{2}\in \mathrm{Z}\text{ : }x=2\pi n_{2}+\pi \text{ and }m\neq 0\right)\end{matrix}\right.$$