Solve r:y=-2x+4

$$r : y = - 2 x + 4$$

Solve for r

$$r=-2y\left(x-2\right)$$

$$y\neq 0$$

Steps for Solving Linear Equation

The equation is in standard form.

$$\frac{1}{y}r=4-2x$$

Divide both sides by y^{-1}.

$$\frac{\frac{1}{y}ry}{1}=\frac{\left(4-2x\right)y}{1}$$

Dividing by y^{-1} undoes the multiplication by y^{-1}.

$$r=\frac{\left(4-2x\right)y}{1}$$

Divide -2x+4 by y^{-1}.

$$r=4y-2xy$$

Solve for x

$$x=-\frac{r}{2y}+2$$

$$y\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by y.

$$r=-2xy+y\times 4$$

Swap sides so that all variable terms are on the left hand side.

$$-2xy+y\times 4=r$$

Subtract y\times 4 from both sides.

$$-2xy=r-y\times 4$$

Multiply -1 and 4 to get -4.

$$-2xy=r-4y$$

The equation is in standard form.

$$\left(-2y\right)x=r-4y$$

Divide both sides by -2y.

$$\frac{\left(-2y\right)x}{-2y}=\frac{r-4y}{-2y}$$

Dividing by -2y undoes the multiplication by -2y.

$$x=\frac{r-4y}{-2y}$$

Divide -4y+r by -2y.

$$x=-\frac{r}{2y}+2$$